JavaScript Recursion With Default Function Parameter

With Fibonacci Example

  April 5, 2022  |  2 minutes  |  230 words  |  Talha Awan

In this post, we will check an example of recursion with default function parameter of es6 JavaScript. Mind you, there is no benefit of doing the recursion this way. On the contrary, it is always better to write a more readable recursion algorithm within the body of the function. This is just for the sake of demonstration!

Fibonacci Example

Fibonacci generator is the most common recursive method. Here’s how its implementation looks like in JavaScript:

const fibonacci = (num) => {
  if (num < 2) {
    return num;
  }
  else {
    return fibonacci(num - 1) + fibonacci(num - 2);
  }
}

console.log(fibonacci(12)); // 144

You can observe the recursion happening when fibonacci is called from within the body of fibonacci. We can do the same recursion using default parameter as below:

const fibonacci = (num = 2, x = num >= 2 ? fibonacci(num - 1) + fibonacci(num - 2) : num) => x;

console.log(fibonacci(12)); // 144

Here note that x is the second parameter in which we conditionally call the fibonacci if num is greater than equal to 2, else we assign num to x. This is the same fibonacci logic we perform in the body of the first example. But here the logic is performed before it even goes to the body of the function.

Again, there’s no conceivable reason why would you do that. So please don’t!

javascript 

See also